Java 8 Convert List to Map
本文通过多个 Java 8 示例,详细演示如何将对象列表(List)转换为映射(Map),并重点讲解如何优雅处理重复键问题,以及如何在转换前排序并保持顺序。
1. 基础转换:Collectors.toMap()
首先定义一个 Hosting 类:
Hosting.java
package com.mkyong.java8;
public class Hosting {
private int Id;
private String name;
private long websites;
public Hosting(int id, String name, long websites) {
Id = id;
this.name = name;
this.websites = websites;
}
// 标准 getter、setter 和 toString() 方法
public int getId() { return Id; }
public void setId(int id) { Id = id; }
public String getName() { return name; }
public void setName(String name) { this.name = name; }
public long getWebsites() { return websites; }
public void setWebsites(long websites) { this.websites = websites; }
@Override
public String toString() {
return "Hosting{" +
"Id=" + Id +
", name='" + name + '\'' +
", websites=" + websites +
'}';
}
}
创建一个 Hosting 对象列表,并使用 Collectors.toMap() 将其转换为 Map。
TestListMap.java
package com.mkyong.java8;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class TestListMap {
public static void main(String[] args) {
List<Hosting> list = new ArrayList<>();
list.add(new Hosting(1, "liquidweb.com", 80000));
list.add(new Hosting(2, "linode.com", 90000));
list.add(new Hosting(3, "digitalocean.com", 120000));
list.add(new Hosting(4, "aws.amazon.com", 200000));
list.add(new Hosting(5, "mkyong.com", 1));
// key = id, value = name
Map<Integer, String> result1 = list.stream().collect(
Collectors.toMap(Hosting::getId, Hosting::getName));
System.out.println("Result 1 : " + result1);
This chapter requires login to view full content. You are viewing a preview.
Login to View Full Content